Use the three steps to solve the problem. the length of a rectangle is 2 inches less than 3 times the number of inches in its width. if the perimeter of the rectangle is 28 inches, what is the width and length of the rectangle? {width a0in., length a1in.}
Accepted Solution
A:
p=28 in l=3*w-2
p=2w+2l p=2w+2*(3w-2) p=2w+6w-2*2 p=8w-4 p=28 in 8w-4=28 8w=28+4 8w=32 in w=32/8=4 in l=3*4-2=12-2=10 in